(6x+7)(x^2-3x+3)=0

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Solution for (6x+7)(x^2-3x+3)=0 equation:


Simplifying
(6x + 7)(x2 + -3x + 3) = 0

Reorder the terms:
(7 + 6x)(x2 + -3x + 3) = 0

Reorder the terms:
(7 + 6x)(3 + -3x + x2) = 0

Multiply (7 + 6x) * (3 + -3x + x2)
(7(3 + -3x + x2) + 6x * (3 + -3x + x2)) = 0
((3 * 7 + -3x * 7 + x2 * 7) + 6x * (3 + -3x + x2)) = 0
((21 + -21x + 7x2) + 6x * (3 + -3x + x2)) = 0
(21 + -21x + 7x2 + (3 * 6x + -3x * 6x + x2 * 6x)) = 0
(21 + -21x + 7x2 + (18x + -18x2 + 6x3)) = 0

Reorder the terms:
(21 + -21x + 18x + 7x2 + -18x2 + 6x3) = 0

Combine like terms: -21x + 18x = -3x
(21 + -3x + 7x2 + -18x2 + 6x3) = 0

Combine like terms: 7x2 + -18x2 = -11x2
(21 + -3x + -11x2 + 6x3) = 0

Solving
21 + -3x + -11x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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